Link : ARIGEOM

Category : Pigeonhole principle

Solution : Consider the first three terms. Some two of them have to be in AP or both in GP, thus giving 6 possible cases. Eg, let a,b,and c be first three terms. If a and b form an AP, then common difference of the AP must be b-a. Now mark all elements falling in this AP as apmarked (remember, all elements must be present in this AP starting from a and ending at some end point within the array). Now for remaining elements, find the common ratio that would mark all remaining elements, and possibly some apmarked elements too. Similarly for other 5 cases too.

Code:

Category : Pigeonhole principle

Solution : Consider the first three terms. Some two of them have to be in AP or both in GP, thus giving 6 possible cases. Eg, let a,b,and c be first three terms. If a and b form an AP, then common difference of the AP must be b-a. Now mark all elements falling in this AP as apmarked (remember, all elements must be present in this AP starting from a and ending at some end point within the array). Now for remaining elements, find the common ratio that would mark all remaining elements, and possibly some apmarked elements too. Similarly for other 5 cases too.

Code:

## No comments:

## Post a Comment